Question

A 2 micro farad capacitor is connected in parallel with another capacitor of 4micro farad. This combination is charged at 300v. What is the total charge of combination and how much energy is stored in it

Answer 1

Answer:

Brainly.in

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Secondary School Physics 5 points

A 2uF capacitor is charged to a potential

difference of 200 V and then isolated. When it is connected across a second uncharged capacitor, the common potential difference becomes 40 V. What is the capacitance of the second capacitor?

A. 2uF

B. 4uF

С. 8uF

D. 8uF

E. 16uF

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Answers

THE BRAINLIEST ANSWER!

rajkumar707

rajkumar707 Ace

Answer:

Initially the charge on the 2uF capacitor is Qi = CV = 2uF x 200V = 400uC =0.4mC

Finally after isolation when it is connected to uncharged capacitor, the amount of charge remains constant.

Using conservation of charge, we get

Qi = Q1 + Q2 = C1V1 + C2V2 = (2uF x 40V) + (C2 x 40V)

400uC = 80uC + (C2 x 40V)

320uC/40V = C2

8uF = C2

The capacitors capacitance is 8uF