Question

A 2 microcoulomb charge is placed at a distance of 0.25 m away from a 3.6 microcoulomb charge. Describe the type of electrostatic force between the charges and calculate the magnitude of the electrostatic force between them.

Answer 1

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Answer 2

The type of force is coulombic force and it is repulsive in nature

F=1.0368N

F=kq1q2/r²(coulombs law)

k=9*10^9

q1=2*10^-6

q2=3.6*10^-6

r=0.25m

therefore force =1.0368N