Question

A 2 Ω resistor and a 6 Ω resistor are connected in series with a 4 V battery. Calculate
the current passing through the circuit.​

Answer 1

Answer:

(a) combined resistance in series= R

1

+R

2

=6+2=8Ω

(b)I=

R

V

=

8

4

=0.5A

(C) p.d across 6 ohm= IR=6×0.5=3V

Answer 2

Answer:

combined resistance in series = R 1+R 2

= 6+2

= 8Ω

I= R/V

= 8/4

= 0.5A

potential difference across 6 ohm = IR

= 6×0.5

= 3V

hope you understand