Question

A 2 Road runs around a circular Park whose sum friends is 88 m find the cost of fencing the outer boundary of the road at the rate of rs 35 per metre

Answer 1

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Circumference = 2πr = 176

π = 22 / 7

2πr = 44r / 7 = 176

r = 7 x 176 / 44

r = 28m

Since, the road is 7m wide and a fence is to be put on the outer boundary, the new radius (r) becomes 7 + 28, which is 35m.

Therefore, circumference = 2 x π x 35

= 2 x 22 x 35 / 7

= 2 x 22 x 5

= 220m

The rate of fencing is Rs. 21 per m

Thus, the cost of fencing = 21 x 220

= Rs. 4620