Question

(a) 2
The H.C.F. of two numbers is 12 and
their L.C.M. is 168. If the sum of
these two numbers is 108, then their
difference is
(a) 36 (b) 48 (c) 60
(d) 72​

Answer 1

Answer

option c .60

Step of explanation

a+b=108 as given

ab=168*12 (product of 2 nos=product of lcm and hcf)

(a-b)^2=(a+b)^2 - 4ab

so we have

(a-b)^2= 108*108 - (4*168*12)

=3600