A 2 V cell is connected to a 1 ohm resistor. How many electrons come out of the negative terminal of the cell in 2 minutes?
Foundation Science - Physics by HC Verma Class 10th.
Answers
Answered by
3
v = 2
r = 1
i = 2
t = 2 min = 120 sec
i = q/t
q= it
q=2 X 120
q = 240
q= ne
n = q/e
n= 240 / 1.6 X 10 ^ -19
n = 240 X 10 ^19 / 1.6
n= 150 X 10^19
n = 1.5 X 10^21
r = 1
i = 2
t = 2 min = 120 sec
i = q/t
q= it
q=2 X 120
q = 240
q= ne
n = q/e
n= 240 / 1.6 X 10 ^ -19
n = 240 X 10 ^19 / 1.6
n= 150 X 10^19
n = 1.5 X 10^21
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Answered by
1
V=2V
T= 2 min= 120sec
we know V=IR
2=I×1
I=2A
now I= q/t
2=q/120 sec
q= 240 C
now q= ne (e= charge of 1 e= 1.6×10^-19)
240=n×1.6×10^-19
n=150×10^19 electrons
T= 2 min= 120sec
we know V=IR
2=I×1
I=2A
now I= q/t
2=q/120 sec
q= 240 C
now q= ne (e= charge of 1 e= 1.6×10^-19)
240=n×1.6×10^-19
n=150×10^19 electrons
hope it helped
alws wlcm
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