Question

A 2 Volt cell is connected to a 1 Ω resistor. How many electrons come out of the negative terminal of the cell in 2 minutes?

Answer 1

Hey.

V = 2 Volt , R = 1 Ω & t = 2 minutes = 120 s

As , Current , I = V/R

so, I = 2/1 = 2 Amperes

Also, Charge, Q = I t

so, Q = 2×120 = 240 Coulomb

As charge on a single electron is

$e \: = 1.6 \times {10}^{ - 19} coulombs$

so, no. of electrons coming out will be

$\frac{q}{e } = \frac{120}{1.6 \times {10}^{ - 19} } = 75 \times {10}^{19} \: electrons$


So, 7.5 × 10^-20 electrons will come out of the negative terminal of the cell in 2 minutes
Hope it helps.

Thanks.

Answer 2

Answer:

here is your answer my frnd

Explanation:

V = 2 Volt , R = 1 Ω & t = 2 minutes = 120 s

As , Current , I = V/R

so, I = 2/1 = 2 Amperes

Also, Charge, Q = I t

so, Q = 2×120 = 240 Coulomb

As charge on a single electron is

so, no. of electrons coming out will be

So, 7.5 × 10^-20 electrons will come out of the negative terminal of the cell in 2 minutes

Hope it helps.

Thanks.

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