Question

(a^2-x^2)x^2 -2ax + 1 factorise​

Answer 1

Answer:

Answer:

\begin{lgathered}x^{2}+\frac{1}{x^{2}}+2-2x-\frac{2}{x}\\=\big(x+\frac{1}{x}\big)\big(x+\frac{1}{x}-2\big)\end{lgathered}x2+x21+2−2x−x2=(x+x1)(x+x1−2)

Step-by-step explanation:

\begin{lgathered}Given ,\\x^{2}+\frac{1}{x^{2}}+2-2x-\frac{2}{x}\end{lgathered}Given,x2+x21+2−2x−x2

=x^{2}+\frac{1}{x^{2}}+2\times x \times \frac{1}{x}-2x-\frac{2}{x}=x2+x21+2×x×x1−2x−x2

=\big(x+\frac{1}{x}\big)^{2}-2\big(x+\frac{1}{x}\big)=(x+x1)2−2(x+x1)

=\big(x+\frac{1}{x}\big)\big(x+\frac{1}{x}-2\big)=(x+x1)(x+x1−2)

Therefore,

\begin{lgathered}x^{2}+\frac{1}{x^{2}}+2-2x-\frac{2}{x}\\=\big(x+\frac{1}{x}\big)\big(x+\frac{1}{x}-2\big)\end{lgathered}x2+x21+2−2x−x2=(x+x1)(x+x1−2)

Step-by-step explanation:

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