Question

a^2/x - b^2/y = 0 and a^2b/x + b^a/y = a+b .Find the value of x and y
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Answer 1

Answer:  The solution is (x, y) = (a², b²).

Step-by-step explanation: The given system of equations to solve is:

Let us consider that

So, equations (i) and (ii) becomes

By the method of cross-multiplication, we have from equations (iii) and (iv) that

             u                        v                         1

-b^2                 0                         a^2                      -b^2

b^2a              -(a+b)                   a^2b                      b^2a

Therefore, we have

Hence, we will get from here that

Thus, the required solution is (x, y) = (a², b²).