(a+2) x²+a+b x+ a×b
a² + (2+-1) a²+ (2×-1)
a²+ a-2
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Step-by-step explanation:
Sum of the roots ⇒a+b=−1 ...(1)
Product of the roots ⇒ab=1 ...(2)
We know that,
(a+b)2=a2+b2+2ab
⇒a2+b2=(a+b)2−2ab
Substituting (1) and (2) in the above equation, we get
⇒a2+b2=(−1)2−2(1)
∴a2+b2=−1
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