Question

A 20.000 N truck is acted upon by a force that decreases its speed from 10 m/s to 5.0 m/s in 5,0 see, What is the average force?​

Answer 1

Weight of truck = 20,000 N

weight = force= mg

w =mg

m=w/g

mass of truck =weight of truck /g

mass of truck =20,000/10= 2×10³ Kg

$\boxed{ \sf \: avg. \: force = m \frac{∆v}{∆t} = ma}$

$\sf \: f = 2 \times {10}^{3} \times \frac{5 - 10}{5}$

$\sf \: f = 2 \times {10}^{3} \times - 1$

$\boxed{ \bold{f = - 2 \times {10}^{3} \: n}}$