Math, asked by yadavabir5, 27 days ago

কোনাে ভাগ অঙ্কে ভাজক (a + 20 -1), ভাগফল (5a -- 14) এবং ভাগশেষ (35a – 17) হলে, ভাজ্য কত হবে? ​

Answers

Answered by sayan05004
0

Answer:

(5a²+ 116a-283)

Step-by-step explanation:

ভাজ্য= (a+20-1)×(5a-14) + (35a -17)

= (a+19)(5a-14) + (35a -17)

=5a²+95a-14a-266+35a-17

=5a²+116a-283

Answered by sandhyadas80508050
0

Answer:

ভাজ্য = ভাজক × ভাগফল + ভাগশেষ

= ( a²+2a-1 ) × ( 5a-14 ) + ( 35a-17 )

= 5a³-14a²+10a²-28a-5a+14+35a-17

= 5a³- 4a²+2a-3

ANSWER:- ভায্য হবে 5a³- 4a²+2a - 3

Step-by-step explanation:

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