Question

(a) 20, 30
(b) 30, 40
(c) 40, 30
(O) ou, ou
1961. 44 g of a sample on complete combustion gives 88 gm CO2 and 36 gm of H 20. The molecular
formula of the compound may be:
(a) C.H.
(b) C2H60
(c) C2H40
(d) C3H60
62. 40 milligram diatomic volatile substance (X) is converted to vapour that displaced 4.92 mL​

Answer 1

Explanation:

1961. 44 g of a sample on complete combustion gives 88 gm CO2 and 36 gm of H 20. The molecular

formula of the compound may be:

(a) C.H.

(b) C2H60

(c) C2H40✔️✔️

(d) C3H60

Answer 2

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(c) C2H40

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