Question

A 20 centimetres long thin wire is formed into a rectangle. If the width of this rectangle is 4 centimetres, what is its length? Also find the area of the rectangle.​

Answer 1

Step-by-step explanation:

20cm=Perimeter

4cm=width

4×2=8

20-8=12

12÷2=6

Therefore length is 6

Area=

24

Answer 2

Answer:

length is 16 cm and area is

${64cm}^{2}$

Step-by-step explanation:

given,

length of wire = 20 cm

breadth of rectangle =4 cm

now, length of wire= perimeter of rectangle

so,

$perimeter \: = 2(l + b)$

so,

$20 = (l + 4)$

so,

$l = 20 - 4$

so,

$l = 16$

now, length is =16cm

so, area of rectangle is =

$l \times b$

so,

$16 \times 4$

so,

${64cm}^{2}$