A 20 cm deep well with daimeter 7 cm is dug the earth from digging is evenly spread out to form a platform 22 cm by 14 cm . find the height of platform
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depth of well, h = 20cm
radius of well, r = 7/2 cm
dimension of platform base = 22cm × 14 cm
height of platform = H
Volume of the well = volume of the platform
πr^2h = 22×14×H
22/7 × 7/2 × 7/2 × 7 = 22×14×H
H = 7×7/(2×2×14) cm
H = 7/8 cm
Height of platform is 7/8 cm
radius of well, r = 7/2 cm
dimension of platform base = 22cm × 14 cm
height of platform = H
Volume of the well = volume of the platform
πr^2h = 22×14×H
22/7 × 7/2 × 7/2 × 7 = 22×14×H
H = 7×7/(2×2×14) cm
H = 7/8 cm
Height of platform is 7/8 cm
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⇒ Given:- Height (h) of well :- 20m
Diameter (d) :- 7 m
Radius (r) :- 7/2 m
Volume of earth platform :- 22 m by 14m
⇒ To find :- Height of the platform:- ?
⇒ Solution:-
Volume of cylinder of radius 7/2 m and height 20 m
Volume of cylinder :- π(r^2)(h)
= 22/7×(7/2^2)×20 m^3
= 770 m^3
Let the height raised by 22 m × 14 m platform be equal to h metres
Therefore,
Volume of the earth in platform = Volume of the earth taken out of the well
22 × 14 × h = 770
h = 770/22 × 14 m
h = 5/2 m
h = 2.5 m
Hence , the height of the platform is 2.5 m.
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