Question

A 20 cm high object is placed 1 to the principal axis of concave mirror the distance of the object from the mirror is 30 and it's image is formed 60 cm from the mirror on the same side of the mirror as the mirror as the object find height

Answer 1

Explanation:

given:

height of object=20cm

u=-30cm

v=-60cm

to find the height of image:

we know that,

magnification=-v/u=height of image/height of object

=-(-60)/-30=h(i)/20

=60/-30=h(i)/20

=-2*20=h(i)

h(i)=-40cm