Question

A 20 feet ladder leans against a wall at height of 16 feet from the ground. How far is the base of the ladder from the wall

Answer 1

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Answer 2

Given:-

• length of ladder is 20 feet.
• length of wall is 16 feet.

To find:-

• base of ladder form the wall?

Solution:-

According to Pythagoras theorem:-

$\dag{ \underline{ \boxed{\rm { \pink{ {h}^{2} = {p}^{2} + {b}^{2} }}}}}$

Where,

• h = 20 feet
• p = 16 feet
• b = (to find)

So,

$\longrightarrow{20}^{2} = {16}^{2} + {b}^{2} \\ \\\longrightarrow 400 = 256 + {b}^{2} \\ \\ \longrightarrow{b}^{2} = 400 - 256 \\ \\ \longrightarrow{b}^{2} = 144 \\ \\ \longrightarrow b = \sqrt{144} \\ \\\longrightarrow \dag { \boxed{ \underline{ \blue{b = 12 \: feet}}}}$

Hence, the measure of base is 144 feet.