A 20 g bullet is short from a 5 kg gun with a velocity of 500 m/s. What is a speed of the recoil of the gun.
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Answer:
The speed of recoil of the gun is 2 m/s.
Explanation:
Mass of bullet, m = 20 g = 0.02 kg
Mass of gun, M = 5 kg
Velocity of bullet, v = 500 m/s
Recoil velocity of the gun, V = ?
Initially, the gun and bullet were at rest, so, the initial momentum of the system is, Pi = 0
After firing the momentum of the system = momentum of gun + momentum of bullet
=> Pf = MV + mv
=> Pf = 5V + (0.02)(500)
=> Pf = 5V + 10
By conservation of momentum,
Pf = Pi
=> 5V + 10 = 0
=> V = -10/5 = -2 m/s
Thus, the recoil velocity of the gun is oppositely directed with respect to the velocity of the bullet.
The speed of recoil of the gun is 2 m/s.
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