Question

A 20 g bullet travelling with a velocity v becomes embedded into a 4 kg

block of wood suspended from two light strings. If the block-bullet

combination rises to a height of 2 m, what is the initial velocity v of the

bullet ?
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Answer 1

Answer:

The situation is as shown in the figure.

Let V be velocity of the block-bullet system just after collision. Then by the law of conservation of linear momentum, we get

mv=(m+M)V

V=

m+M

mv

Let the block rises to a height h.

According to law of conservation of mechanical energy,

we get

2

1

(m+M)V

2

=(m+M)gh

h=

2g

V

2

=

2g

v

2

(

m+M

m

)

2

.

Step-by-step explanation:

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Answer 2

Answer:

2 is a answer

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