A 20 g mass of naoh is dissolved in water. molarity of solution is
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Answer:
Step-by-step explanation:
Molality = Moles of solute/ kilograms of solvent
Moles of NaOH =( 20 gm of NaOH × 1 mole of NaOH) ÷ molar mass of NaoH
= 20*1/40 = 1/2 = 0.5 moles of NaOH
Density =mass/ Volume
Density of water = 1.08 g/ cm^3
Volume = 500 cm^3 ( given)
1.08 =mass/ volume
1.08 = mass/ 500
1.08× 500 = mass
Mass of water = 500gm ( approximately)
Kilogram of water = (500g of water x 1 kg of water)÷1000 gm of water.
= 500/1000=5/ 10 = 1/2 = 0.5 Kg of water
Molality = moles of solute/ kilograms of solvent
= 0.5/0.5 = 1mole/kgm
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