Question

A 20 gm bullet is fired with velocity of 600 m/s into a wooden block of mass 4.5 kg at rest uk = 0.4. The block will move

Answer 1

Answer:

As we have learned

Coefficient of Friction(µ) -

Ratio of static friction to the normal = F/R

After coliision , common velocity

v = 600 * 20

-------- = 17.14 m/s

700

\mu = 0.6

Decelleartion a =

ųg = 0.6 * 9.8 = 5.88 m/s^2

Distance travelled S =

= u^2 ( 17.14 )^2

---- = --------- = 24.98 m

2a 2 * 5.88

APPROX. 25 m

I HOPE IT WILL HELP YOU ...