a 20 gram of bullet is shot from a 5 kg gun with the velocity of 500 miles per second what is the speed of recoil of the gun
Answers
Answer:
Mass of bullet 'm' = 0.02kg
Mass of gun 'M' = 5kg
Speed of the bullet 'u' = 500m/s (meters per second)
recoil speed of the gun 'v' = ?
Using the conservation of momentum,
Initial momentum of the gun bullet system = final momentum of the system
Initial momentum = 0
Final momentum = mu + Mv
0 = mu + Mv
v = -mu/M = -(0.02*500)/5 = -10/5 = -2m/s (minus infront of 2 mean guns velocity is in the opposite direction to bullets velocity)
recoil speed 'v' = 2m/s.
Answer:
Answer:
Mass of bullet 'm' = 0.02kg
Mass of gun 'M' = 5kg
Speed of the bullet 'u' = 500m/s (meters per second)
recoil speed of the gun 'v' = ?
Using the conservation of momentum,
Initial momentum of the gun bullet system = final momentum of the system
Initial momentum = 0
Final momentum = mu + Mv
0 = mu + Mv
v = -mu/M = -(0.02*500)/5 = -10/5 = -2m/s (minus infront of 2 mean guns velocity is in the opposite direction to bullets velocity)
recoil speed 'v' = 2m/s.