Question

A 20 kg block is pushed up along an incline that makes an angle of 30 to the

horizontal. The block starts moving with an initial speed of 4 m/s at the bottom of the

incline, and stops after moving 8 m up the incline. Find the magnitude of the net force

acting on the block during its entire motion. (Take the upward direction as positive

direction)​

Answer 1

Answer:

Balancing forces along the inclined plane, Fcosθ=mgsinθ+f

f=80N;θ=30

o

is frictional force.

So, Fcos30

o

=200sin30

o

+80⇒F=205.55N

Explanation:

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Answer 2

Answer:

20kg

Explanation: