A 20 kg Block moving East at 30 ms collides with a 25 kg Block of rest. The two block stick together. What is the final speed of two Blocks ?
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Answered by
0
Answer
Correct option is
B
800 Joule
As there is no external non-conservative force on the system (both masses altogether) the linear momentum should
be conserved.
Thus we should have m
1
v
1
+m
2
v
2
=(m
1
+m
2
)V (inelastic collision)
V is the common velocity after the collision.
putting values we get 20(10)+5(0)=(20+5)V or V=8m/s
so the new KE will be K=
2
1
mV
2
=0.5×25×64=800Joule
Answered by
0
Answer:
As there is no external non-conservative force on the system (both masses altogether) the linear momentum should
be conserved.
Thus we should have m
1
v
1
+m
2
v
2
=(m
1
+m
2
)V (inelastic collision)
V is the common velocity after the collision.
putting values we get 20(10)+5(0)=(20+5)V or V=8m/s
so the new KE will be K=
2
1
mV
2
=0.5×25×64=800Joule
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