Question

A 20 kg crate hangs at the end of a long rope. Find its acceleration when the tension in
the rope is
(a) 250 N
(b) 150 N
(c) zero
(d) 196 N​

Answer 1

Answer:

mg + ma = T

m (g+a) = T

m = 20 kg

g = 10 m/s2

Explanation:

i) T= 250

20 (10)+ 20 a = 250-------------------------( i)

20 a = 250 -200

a = 50/20 = 2.5 m/s2

ii) T = 150 N

from (i)

20a = 150 - 200 = -50

a = -2.5 m/s2

íii) T = 0

from (i) 20a = -200

a = -10 m/s2

iv) eq (i) 20a = 196 -200

a = -4 /20

a = -0.2 m/s2

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