A 20 kg kid is sitting in a 60 kg boat in a lake. The distance of kid from the bank of lake is 20 m. If the kid moves 8m on the boat towards the bank, then find the distance of kid from the bank. The system is initially at rest and there is no friction between boat and water.
Answers
Explanation:
The man moves with a speed of 1.5 m/sec for 4 sec . So distance travelled by the man during this time period is 6 m. Let us assume the shore is to our left , when the moves towards the shore there will be a relative displacement of boat towards right . So the relative displacement of boat is = md/(M+m) , where m is mass of man ,and d is the distance he walks towards the shore and M is the mass of boat .after substituting the values given we get the relative displacement to be1.8m.so the total distance from the shore is = initial distance from the shore – distance walked by the man + relative displacement of boat = 20-6+1.8=15.8m
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Answer:
m1v1 = (m1 + m2)v
m1 ∆r1/∆t = (m1 + m2)∆r/∆t
20 × 8 = (20+60) x
160 = 80x
x = 2
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