Question

A 20 kg of load is suspended by a wire of cross section 0.4 mm2 the stress produced in n/m2 is

Answer 1

Answer:

4.9 * 10^8

Explanation:

Stress = F/A

∴Stress = mg/A

∴Stress = 20*9.8/0.4*10^ -6  

∴Stress = 4.9 * 10^8 N/m^2