Math, asked by sundasjabeen14ml, 1 month ago


A 20-lb weight stretches a spring 6 inches. The weight is released from rest 6
inches below the equilibrium position.
Find the position of the weight at t = π\12 ,π\8,π/ 6 ,π\4 ,π/32
second​

Answers

Answered by sohamraj0809
0

Step-by-step explanation:

A 20-lb weight stretches a spring 6 inches. The weight is released from rest 6

inches below the equilibrium position.

Find the position of the weight at t = π\12 ,π\8,π/ 6 ,π\4 ,π/32

second

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