Chemistry, asked by adsf129, 9 months ago

A 20 litres mixture contains milk and water in the respective ratio of 3 : 2. Then 10 litres of the mixture is removed and replaced with pure milk and the operation is repeated once more. At the end of the two removals and replacements, what is the ratio of milk and water in the resulting mixture respectively

Answers

Answered by Anonymous
0

Milk in container earlier=(4/5)*45=36 L

Water in container earlier=(1/5)*45=9 L

Now required milk:water ratio=3:2

Suppose we add x L of water in container,then;

36/(9+x)=3:2

solving we get x=15 L

Therefore 15 L of water required to make ratio 3:2

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