a 20 m deep well with diameter 7 cm is dug and the earth from digging is evenly spread out to form a platform 22m by 14 M then the height of the platform is
Answers
⇒ Given:- Height (h) of well :- 20m
Diameter (d) :- 7 m
Radius (r) :- 7/2 m
Volume of earth platform :- 22 m by 14m
⇒ To find :- Height of the platform:- ?
⇒ Solution:-
Volume of cylinder of radius 7/2 m and height 20 m
Volume of cylinder :- π(r^2)(h)
= 22/7×(7/2^2)×20 m^3
= 770 m^3
Let the height raised by 22 m × 14 m platform be equal to h metres
Therefore,
Volume of the earth in platform = Volume of the earth taken out of the well
22 × 14 × h = 770
h = 770/22 × 14 m
h = 5/2 m
h = 2.5 m
Hence , the height of the platform is 2.5 m.
Answer:
Step-by-step explanation:
Diamter = 7 m
so, radius = 3.5 m
Earth dug out from (cylindrical) well
=π×r×r×h
=22\7
×3.5×3.5×20
=770m
3 to from platform ...... (cuboidal)
volume of cuboid = l×b×h
770=22×14×h
so, height = 22
770×14=2.5m