a 20 m deep well with diameter 7 M is dug and the earth from digging is evenly spread out to form a platform 22 m by 14 M find the height of a platform?
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Answered by
12
diameter= 7m
so, radius = 3.5m
-earth dug out from (cylindrical) well
=pi×r×r×h
=22/7×3.5×3.5×20
=770
to form platform ... ( cuboidical)
volume of cuboid=l×b×h
770 =22×14×h
so, height=770/22×14
= 2.5m
so, radius = 3.5m
-earth dug out from (cylindrical) well
=pi×r×r×h
=22/7×3.5×3.5×20
=770
to form platform ... ( cuboidical)
volume of cuboid=l×b×h
770 =22×14×h
so, height=770/22×14
= 2.5m
Answered by
10
Given, height of the well=20m
Diameter =7m=7/2m
Volume of the well= pir2h
=22/7×7/2×7/2×20
=22×7×5m
=770m3
Now, Lenght of the plot =22m
Breadth of the plot =14 m
Area =l×b
=14×22
=308m2
Therefore, Height of the platform formed =Volume of well/area of plot
=770/308=2.5m
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