A 20 m deep well with diameter 7 m is dug and the earth from digging is evenly spread out to from a platform 22 m by 14 m find the height of the platform
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Answer...-
Diameter = 7 m
Radius = 7/2 m
Height = 20
Earth dug out from well (cylindrical) and From platform (cuboidal shape)
volume of cuboid = length × breath × Height ( l × b × h )
length = 22 m
breath = 14 m
height = ?
πr^2h = area of platform × height of platform
= 22/7 × (7/2)^2 × 20 = 22 × 14 × h
h = 22/7 × 49/4 × 20/22×14
h = 5/2 = 2.5 m
Hence, the height of such a platform will be 2.5 m
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