A 20 m long chain of linear mass density 0.4 kg m–1 is hanging freely from a rigid support. The power required to lift the chain upto the point of support in 2 s is
Answers
Answered by
10
first of all find centre of gravity of chain.
here centre of gravity lies at the centre of length of chain . e.g., C.O.G = h = 10m/2 = 5m
given, mass density = 0.4 kg/m
length of chain , l = 20m
so, mass of chain = l × mass density
= 20 × 0.4 = 8 kg
so, potential energy of chain = mgh
= 8 × 10 × 5 = 400J
power = energy/time,
so, power = 400/2 = 200W
hence, power required to lift the chain upto the point of support in 2 s is 200W
here centre of gravity lies at the centre of length of chain . e.g., C.O.G = h = 10m/2 = 5m
given, mass density = 0.4 kg/m
length of chain , l = 20m
so, mass of chain = l × mass density
= 20 × 0.4 = 8 kg
so, potential energy of chain = mgh
= 8 × 10 × 5 = 400J
power = energy/time,
so, power = 400/2 = 200W
hence, power required to lift the chain upto the point of support in 2 s is 200W
Similar questions