Question

a 20 mg railroad car moving with 0.5 m/s speed to the right collides with 35 mg car which is at the rest. the coefficient of restitution between the two cars is e=0.05. determine the speed of the cars after collision

Answer 1

Given that,

Mass of railroad = 20 mg

Speed = 0.5 m/s

Mass of car = 35 mg

Coefficient of restitution = 0.05

We need to calculate the speed of car

Using conservation of momentum

$m_{r}u_{r}+m_{c}u_{c}=(m_{r}+m_{c})v$

$v=\dfrac{m_{r}u_{r}+m_{c}u_{c}}{(m_{r}+m_{c})}$

Put the value into the formula

$v=\dfrac{20\times0.5+0}{(35+20)}$

$v=0.18\ m/s$

Hence, The speed of the cars after collision is 0.18 m/s,