Physics, asked by madiham2900, 1 year ago

A 20 N metal block is suspended by a spring balance . a beaker containing some water is placed on a weighing which reads 40 N . the spring balance is now lowered so that the block gets immersed in water . the spring balance now reads 16 N . Find the reading of weighing machine.

Answers

Answered by ariston
61

Answer: 44 N

Explanation:

A metal block suspended by a spring balance weighs 20 N.

When dipped in water, It weighs 16 N.

The net drop in weight = 20 N-16 N = 4 N. This drop is due to buoyant force which equal to the weight of the volume of the water displaced by the immersed water.

4 N acts in upward direction.

The weighing machine measures the normal force.

Hence, with the block immersed in water, the weighing machine would now read 40 N + 4 N = 44 N

Answered by irfanshaik25
20
When the metal block is immersed in water, the spring balance reading decreased by 4N (20N- 16N).
So, according to Newton’s third law of motion, this 4N will be added to the reading on the weighing machine.
Therefore, the new reading on the weighing machine will be
40N+ 4N=44N.
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