A 20 N metal block is suspended by a spring balance . a beaker containing some water is placed on a weighing which reads 40 N . the spring balance is now lowered so that the block gets immersed in water . the spring balance now reads 16 N . Find the reading of weighing machine.
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Answered by
61
Answer: 44 N
Explanation:
A metal block suspended by a spring balance weighs 20 N.
When dipped in water, It weighs 16 N.
The net drop in weight = 20 N-16 N = 4 N. This drop is due to buoyant force which equal to the weight of the volume of the water displaced by the immersed water.
4 N acts in upward direction.
The weighing machine measures the normal force.
Hence, with the block immersed in water, the weighing machine would now read 40 N + 4 N = 44 N
Answered by
20
When the metal block is immersed in water, the spring balance reading decreased by 4N (20N- 16N).
So, according to Newton’s third law of motion, this 4N will be added to the reading on the weighing machine.
Therefore, the new reading on the weighing machine will be
40N+ 4N=44N.
So, according to Newton’s third law of motion, this 4N will be added to the reading on the weighing machine.
Therefore, the new reading on the weighing machine will be
40N+ 4N=44N.
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