Question

A 20 uF capacitor is charged to 1 kV potential and then
its plates are connected by a conducting wire. How
much heat would be produced?
5 J
10 J
15 J
20 J​

Answer 1

Answer:

10J

Explanation:

Heat produced = Energy stored in capacitor

Energy = 1/2CV²

            = 1/2 x 20 x 10⁻⁶ x (1000)²

            = 10 J

I hope it helps.

Answer 2

Given:

A 20 uF capacitor is charged to 1 kV potential and then its plates are connected by a conducting wire.

To find:

Heat produced?

Calculation:

The net energy stored between the plates of a parallel plate capacitor is ½CV².

• Now, upon connecting the plates with a conducting wire the whole energy stored will be converted into heat energy.

• Let heat energy be H :

$\rm \: H= \dfrac{1}{2} \times C \times {V}^{2}$

$\rm \implies H= \dfrac{1}{2} \times (20 \times {10}^{ - 6} )\times {(1\times 1000)}^{2}$

$\rm \implies H= \dfrac{1}{2} \times (2 \times {10}^{ - 5} )\times {( {10}^{3} )}^{2}$

$\rm \implies H= {10}^{ - 5} \times {10}^{6}$

$\rm \implies H= {10}^{6 - 5}$

$\rm \implies H= 10 \: joule$

So, heat produced in the wire is 10 Joules.