Question

A 20 W source of sound of angular frequency 6000
rad/s sends out waves in air. Find the displacement
amplitude of the wave at a distance of 1 m from the
source. (Speed of sound in air = 340 m/s, density of air
= 1.3 kg/mº)​

Answer 1

Answer:

the displacement  amplitude of the wave at a distance of 1 m from the  source is $A = 1.41 \times 10^{-5} m$

Explanation:

As we know that the intensity of sound source at some distance from it is given as

$I = \frac{P}{Area}$

so we have

$I = \frac{P}{4\pi r^2}$

so we have

$I = \frac{20}{4\pi (1^2)}$

$I = 1.59 W/m^2$

now we know that intensity of wave is given as

$I = \frac{1}{2}\rho A^2 \omega^2 v_o$

so we have

$1.59 = \frac{1}{2}(1.3)A^2(6000)^2(340)$

$1.59 = 7.96\times 10^9 A^2$

$A = 1.41 \times 10^{-5} m$

#Learn

Topic : Intensity of wave

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