Question

A 200 m train moving at 11 m/s crosses a man running on the platform along the same direction in 20 sec. Then the speed of man is

Answer 1

let the speed of the man be x m/s

speed of the train= 200 m/s

Distance = speed x time

200m (length of train)= (20-x) x 20 s

(man's speed to be subtracted as he is also running)

so x= 10 m/s

When train and man are in opposite direction

200 m = (20+10) t

so t=20/3 seconds

Hope this helps!