Question

a 200 ohm resistor a voltmeter and are 2 volt cell of negligible internal resistance are connected in series the world Hotel rates 1 volt find the resistance of the voltmeter and the current in the circuit​

Answer 1

Answer:Rv=200 ohm and i=5×10^-3 A

Explanation

Ammeter is always connected in series

Resistance of circuit is combined resistance of voltmeter and internal resistance

R=Rv+r

since r=neglegible

Therefore

Rv=R=200 ohm

And current

By ohm's law,

i=V/R

=1/200

=5×10^-5 A

Answer 2

Answer:

200ohm &5×10^-3A

Explanation:

I=V/R=1/200A=5×10^-3A

Let voltmeter resistance be R

E=IR+1V

2V-1V=R/200

1V=R/200

1×200=R

200ohm=R