A 200 W bulb emits monochromatic light of wavelength 1400 Å and only 10% of the energy is emitted as light. The number of photons emitted
by the bulb per second will be
(1) 1.4 x 10^18
(2) 1.4 x 10^20
(3) 1.4 x 10^19
(4) 1.4 x 10^21
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Answer: c) 1.4×10^19
Explanation:
Total energy =200 J
As given only 10% of energy is used
10% of 200 =20J
Energy of one photon = hc/
λ
=6.625×10^-34×3×10^8/14×10^-8
=14.4×10^-19
Number of photons =Total Energy/Energy of one proton
N=(20÷14.4)×10^19
=1.4 ×10^19
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