A 2000 kg vehicle is moving with a speed of 20 ms-1 is brought to rest in a distance of 50 meter by applying
brakes. What is the acceleration and unbalanced force acting on the body?
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Answered by
1
Answer:
Correct option is
A
−4000N
Given,
Initial velocity(u)=20ms
−1
Final velocity(v)=0
Distance moved(S)=50m
We know,
v
2
=u
2
+2aS
0=20
2
+2a×50
−400=100a
a=
100
−400
a=−4ms
−2
Now,
F=ma
F=1000×−4
=−4000N
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Answer:
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