Question

a 2000kg car has to go over a turn whose radius

Answer 1

Answer: Maximum speed: 67.18 m/s

Given:

Radius = 750 m

                    $\Theta = 5^{\circ}$

The coefficient of friction $\mu_s$ = 0.5

Solution:

Formula for maximum speed $V_{max} = \sqrt{r \times g [sin\Theta+\mu_s cos\Theta]/ [cos\Theta-\mu_s sin\Theta]}$

where g = 9.8 m/s2

               $V_{max} = \sqrt {750 \times 9.8 [sin(5^{\circ}) + (0.5)cos(5^{\circ})] / [cos(5^{\circ}) - (0.5) sin(5^{\circ})]}$

               $V_{max} = \sqrt {750 \times 9.8 [(0.087) + (0.5)(0.996)] / [(0.996) - (0.5)(0.087)]}$

               $V_{max} = \sqrt { 7350 [(0.087) + (0.498)] / [(0.996)-(0.0435)]}$

               $V_{max} = \sqrt {7350 (0.585) / (0.9525)}$

               $V_{max} = \sqrt {4514.173}$

               $V_{max} = 67.18 m/s$

Answer 2

Answer:

can u tell me this question is taken from which book ??