A 200kg motorcycle is moving over a horizontal road with uniform velocity. If stopped with a negative acceleration of 1.5/s², hen what is the force of friction between the tyre of the motorcycle and the road?
Answers
Answered by
3
M=200 KG
A=1.5 M/S²
F=?
F=MA,FROM THIS FORMULA WE CAN EAISLY FIND F.
F=200*1.5
F=300 NEWTON
AAYA SAMAJ ME.
Answered by
0
Answer:
The motor cycle was moving on the road with a constant velocity . Now , due to friction between the tyres and the road , the motorcycle stops . Hence ,the friction act as the stopping force for the object.
.: friction = stopping force
friction = mass x acceleration
friction = 200 x 1.5
friction = 300N
Similar questions