Question

A 200kg motorcycle is moving over a horizontal road with uniform velocity. If stopped with a negative acceleration of 1.5/s², hen what is the force of friction between the tyre of the motorcycle and the road? ​

Answer 1

M=200 KG

A=1.5 M/S²

F=?

F=MA,FROM THIS FORMULA WE CAN EAISLY FIND F.

F=200*1.5

F=300 NEWTON

AAYA SAMAJ ME.

Answer 2

Answer:

The motor cycle was moving on the road with a constant velocity . Now , due to friction between the tyres and the road , the motorcycle stops . Hence ,the friction act as the stopping force for the object.

.: friction = stopping force

friction = mass x acceleration

friction = 200 x 1.5

friction = 300N