A 200kg motorcycle is moving over a horizontal road with uniform velocity. If stopped with a negative acceleration of 1.5/s², hen what is the force of friction between the tyre of the motorcycle and the road?
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M=200 KG
A=1.5 M/S²
F=M*A
FROM THE FORMULA ,WE CAN EAISLY FIND FORCE.
F=200X1.5
F=300 NEWTON
AAYA SAMAJ ME.
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