a 200liters solution of alcohol and water contain 1/4th part alcohol. find the new % of alcohol , if 50 liters of original solution is replaced by 50 liters of alcohol.
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amount of alcohol in old solution is 1/4 of 200
=50 liter
amount of water in old=150liter.
new amount of alcohol is= 37.5+50= 87.5liter
amount of water is as it is.
so new %of alcohol= (87.5÷200)×100
=43.75%
=50 liter
amount of water in old=150liter.
new amount of alcohol is= 37.5+50= 87.5liter
amount of water is as it is.
so new %of alcohol= (87.5÷200)×100
=43.75%
poonambisht91:
options is (a) 43.75% (b) 50%. (c)66.66%. (d) 80%. (e) non of these
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