Question

A 200v , shunt motor developes 23 H.P , when taking 20.2 KW . The filed resistance is 50 ohm and armature resistance is 0.06 ohm . what are the total copper losses?​

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

The copper losses of shunt motor is 564.54W

Explanation:

Given that,A 200v shunt motor develops 23 H.P output when taking 20.2 KW of power.The filed resistance is 50 ohm and armature resistance is 0.06 ohm.We are required to fin the total copper losses.

First we convert the output power in kilowatt units as shown

$P_{out}=23\times746=17158W=17.158kW$

The input power is given as $P_{in}=20.2kW$

Therefore total losses are $P_{in}-P_{out}=20.2-17.158=3042W$

And the input current is the ratio of Input power to the voltage of the shunt motor.Hence,$i_{inp}=\frac{20200}{200} =101A$

The shunt current is the ratio of voltage to the filed resistance.Hence,

$i_{sh}=\frac{200}{50} =4A$

Therefore the armature current is the difference of input current and shunt current.Hence,$i_{a}=101-4=97A$

Now,the total copper losses is the product of armature resistance to the square of the armature current.Hence,Mathematically we write-

$Cu_{loss}=i_{a}^{2} R_{a}$

Substituting the values in above relation,we get-

$Cu_{loss}=97^{2} \times0.06=564.54W$

Therefore,the copper losses of shunt motor is 564.54W

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