Math, asked by rohitantony9a, 7 months ago

a^2020*b^2019 = 1/2 and a^2018*b^2021 = (64)^1/2, then a^2b^3 =

Answers

Answered by trickymind5
1

a/b = 1/4

So a=1, b = 4

a^2b^3 = 1^2(4)^3 = 1

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