A 20g chunk of dry ice is placed in an empty 0.75 litre wire bottle tightly closed what would be the final pressure in the bottle after all CO2 has been evaporated and temperature reaches to 25°C?
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Answer:
w = 20g dry CO2 which will evaporate to develop pressure
m = 44, V = 0.75 litre, P = ? T = 298K
PV = W / m RT
P × 0.75 = 20 / 44 5 0.0821 × 298
P = 14.228 atm
Pressure inside the bottle = P + atm pressure = 14.828 + 1 = 15.828 atm
Answered by
2
Explanation:
w = 20 g dry CO2
which will evaporate to develop pressure.
m = 44, V = 0.75 L, P = ?, T = 298 K
P = w/m × RT (as PV = nRT & n = w/m)
P × 0.75 = 20/44 × 20/4450.0821 × 298.
P = 14.828 atm
Pressure inside the bottle = P + atm pressure.
= 14.828 + 1 = 15.828atm
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