Question

A 20g piece of lead absorbs 566 joules of heat and its temperature changes from 35 oC to 195 oC. Calculate the specific heat.

Answer 1

We should use the formula : Q = mcΔt

where Q = energy supplied, m = mass, c = specific heat capacity and Δt = change in temperature

So after making c the subject of formula :

$c = \frac{Q}{mΔt}$

= $\frac{566}{(160)(0.02)}$  , NB : 0.02 is mass changed to kg

= 176.875 J / ( kg°C )

∴ specific heat capacity = 176.875 J / ( kg°C )

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