A 20gm particle moves in SHM with a frequency of 3 oscillations per second and amplitude of 5cm.Through what total distance does the particle move during one oscillation? What is its average speed?
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Answer:
Given : SHM particle having 3 oscillations in 1 second. Amplitude of
5 cm.
To find : Total distance in one oscillation and average speed.
Definitions: Time period is the time taken to complete one complete oscillation by the particle undergoing SHM.
Calculation:
Amplitude = 5cm
So total distance travelled in one complete oscillation
= 4 times of amplitude
= 4 * 5
= 20 cm.
Now 3 oscillations in 1 second
=> therefore 1 oscillation in 1/3 second.
Average speed
= (total distance/total time)
= (20)/(1/3)
= 20*3
= 60 cm/sec.
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